A multiset (also known as a bag) is a data structure similar to a regular set, but it can store multiple instances of the same element.
For example, if I added the elements 1, 2, 2 to a regular set, the set would only contain two items, since adding 2 a second time has no effect.
var set = Set<Int>()
set.add(1) // set is now [1]
set.add(2) // set is now [1, 2]
set.add(2) // set is still [1, 2]
By comparison, after adding the elements 1, 2, 2 to a multiset, it would contain three items.
var set = Multiset<Int>()
set.add(1) // set is now [1]
set.add(2) // set is now [1, 2]
set.add(2) // set is now [1, 2, 2]
You might be thinking that this looks an awful lot like an array. So why would you use a multiset? Let's consider the differences between the two…
Typical operations on a multiset are:
One real-world use of multisets is to determine whether one string is a partial anagram of another. For example, the word "cacti" is a partial anagrams of "tactical". (In other words, I can rearrange the letters of "tactical" to make "cacti", with some letters left over.)
var cacti = Multiset<Character>("cacti")
var tactical = Multiset<Character>("tactical")
cacti.isSubSet(of: tactical) // true!
Under the hood, this implementation of Multiset uses a dictionary to store a mapping of elements to the number of times they've been added.
Here's the essence of it:
public struct Multiset<Element: Hashable> {
private var storage: [Element: UInt] = [:]
public init() {}
And here's how you'd use this class to create a multiset of strings:
var set = Multiset<String>()
Adding an element is a case of incrementing the counter for that element, or setting it to 1 if it doesn't already exist:
public mutating func add (_ elem: Element) {
storage[elem, default: 0] += 1
}
Here's how you'd use this method to add to the set we created earlier:
set.add("foo")
set.add("foo")
set.allItems // returns ["foo", "foo"]
Our set now contains two elements, both the string "foo".
Removing an element works much the same way as adding; decrement the counter for the element, or remove it from the underlying dictionary if its value is 1 before removal.
public mutating func remove (_ elem: Element) {
if let currentCount = storage[elem] {
if currentCount > 1 {
storage[elem] = currentCount - 1
} else {
storage.removeValue(forKey: elem)
}
}
}
Getting the count for an item is simple: we just return the value for the given item in the internal dictionary.
public func count(for key: Element) -> UInt {
return storage[key] ?? 0
}
Written for the Swift Algorithm Club by Simon Whitaker